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MySQL日期格式DD / MM / YYYY选择查询？

2024-04-22 12:27:04 448

使用select格式化日期DD/MM/YYYY并按降序排列。语法如下-

SELECT *FROM yourTableName
where yourDatetimeColumnName order by
STR_TO_DATE(yourDatetimeColumnName,’%d/%m%Y’) desc;

上面的语法将按降序给出日期。为了理解上述语法，让我们首先创建一个表。创建表的查询如下-

mysql> create table DateFormatWithSelect
   -> (
   -> UserId int,
   -> UserName varchar(100),
   -> UserLoginDatetime varchar(100)
   -> );

使用insert命令在表中插入一些记录。查询如下-

mysql> insert into DateFormatWithSelect values(101,'John','20/10/2016');

mysql> insert into DateFormatWithSelect values(102,'David','21/09/2015');

mysql> insert into DateFormatWithSelect values(103,'Carol','21/12/2018');

mysql> insert into DateFormatWithSelect values(104,'Mike','2/8/2014');

mysql> insert into DateFormatWithSelect values(105,'Sam','21/11/2017');

mysql> insert into DateFormatWithSelect values(106,'Bob','21/12/2013');

使用select命令显示表中的所有记录。查询如下-

mysql> select *from DateFormatWithSelect;

以下是输出-

+--------+----------+-------------------+
| UserId | UserName | UserLoginDatetime |
+--------+----------+-------------------+
|    101 | John     | 20/10/2016        |
|    102 | David    | 21/09/2015        |
|    103 | Carol    | 21/12/2018        |
|    104 | Mike     | 2/8/2014          |
|    105 | Sam      | 21/11/2017        |
|    106 | Bob      | 21/12/2013        |
+--------+----------+-------------------+
6 rows in set (0.00 sec)

这是将日期格式化为DD/MM/YYYY格式的SELECT-

mysql> select *from DateFormatWithSelect
   -> where UserLoginDatetime order by str_to_date(UserLoginDatetime,'%d/%m/%Y') desc;

输出结果

+--------+----------+-------------------+
| UserId | UserName | UserLoginDatetime |
+--------+----------+-------------------+
|    103 | Carol    | 21/12/2018        |
|    105 | Sam      | 21/11/2017        |
|    101 | John     | 20/10/2016        |
|    102 | David    | 21/09/2015        |
|    104 | Mike     | 2/8/2014          |
|    106 | Bob      | 21/12/2013        |
+--------+----------+-------------------+
6 rows in set, 6 warnings (0.00 sec)

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MySQL日期格式DD / MM / YYYY选择查询？

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