MySQL查询以选择具有特定日期的记录?
您可以使用DATE()
MySQL来选择具有特定日期的记录。语法如下。
SELECT *from yourTableName WHERE DATE(yourDateColumnName)=’anyDate’;
为了理解上述语法,让我们首先创建一个表。创建表的查询如下。
mysql> create table AllRecordsFromadate -> ( -> Id int, -> Name varchar(100), -> Age int, -> AdmissionDate datetime -> );
使用insert命令在表中插入一些记录。插入记录的查询如下。
mysql> insert into AllRecordsFromadate values(101,'John',23,'2018-10-13'); mysql> insert into AllRecordsFromadate values(102,'Carol',24,'2014-12-5 12:34:50'); mysql> insert into AllRecordsFromadate values(103,'Mike',25,'2014-12-5 12:30:40'); mysql> insert into AllRecordsFromadate values(104,'Bob',24,'2015-10-7 11:10:20'); mysql> insert into AllRecordsFromadate values(105,'Sam',25,'2011-6-26 10:10:20');
使用select命令显示表中的所有记录。查询如下-
mysql> select *from AllRecordsFromadate;
以下是输出。
+------+-------+------+---------------------+ | Id | Name | Age | AdmissionDate | +------+-------+------+---------------------+ | 101 | John | 23 | 2018-10-13 00:00:00 | | 102 | Carol | 24 | 2014-12-05 12:34:50 | | 103 | Mike | 25 | 2014-12-05 12:30:40 | | 104 | Bob | 24 | 2015-10-07 11:10:20 | | 105 | Sam | 25 | 2011-06-26 10:10:20 | +------+-------+------+---------------------+ 5 rows in set (0.00 sec)