检查Disarium号-JavaScript
DisariumNumber-满足以下等式的所有数字均为dDisariumnumber-
xy...z = x^1 + y^2 + ... + z^n
其中n是数字中的位数。
例如-
175 is a disarium number be: 175 = 1^1 + 7^2 + 5^3 = 1 + 49 + 125 = 175
让我们为该函数编写代码-
示例
以下是代码-
const num = 175;
const isDisarium = num => {
const res = String(num)
.split("")
.reduce((acc, val, ind) => {
acc += Math.pow(+val, ind+1);
return acc;
}, 0);
return res === num;
};
console.log(isDisarium(num));
console.log(isDisarium(32));
console.log(isDisarium(4334));输出结果
控制台中的输出：-
true false false