循环排序的C ++程序?
循环排序是一种就地,不稳定的排序算法,这是一种比较排序,在理论上,对原始数组的总写入数是最佳的,这不同于其他任何就地排序算法。基于这样的思想,可以将要排序的排列分解为多个周期,可以将其单独旋转以给出排序的结果。
与几乎所有其他类型不同,项目永远不会被写入数组中的其他地方,仅仅是为了将它们推到行动之外。如果每个值已经在正确的位置,则将其写入零次,或者将一次写入其正确的位置。这与完成就地排序所需的最少重写次数相匹配。
当对一些庞大的数据集进行写操作非常昂贵时,例如在诸如EEPROM之类的EEPROM中,每次写操作都会减少存储器的使用寿命,因此将写操作的次数减到最少很有用。
Input: a[]={7,4,3,5,2,1,6} Output: 1 2 3 4 5 6 7
说明
arr[] = {10, 5, 2, 3} index = 0 1 2 3 cycle_start = 0 item = 10 = arr[0] Find position where we put the item, pos = cycle_start while (arr[i] < item) pos++; We put 10 at arr[3] and change item to old value of arr[3]. arr[] = {10, 5, 2, 10} item = 3 Again rotate rest cycle that start with index '0' Find position where we put the item = 3 we swap item with element at arr[1] now arr[] = {10, 3, 2, 10} item = 5 Again rotate rest cycle that start with index '0' and item = 5 we swap item with element at arr[2]. arr[] = {10, 3, 5, 10 } item = 2 Again rotate rest cycle that start with index '0' and item = 2 arr[] = {2, 3, 5, 10} Above is one iteration for cycle_stat = 0. Repeat above steps for cycle_start = 1, 2, ..n-2
示例
#include<iostream> using namespace std; void cycleSort(int a[], int n) { int writes = 0; for (int c_start = 0; c_start <= n - 2; c_start++) { int item = a[c_start]; int pos = c_start; for (int i = c_start + 1; i < n; i++) if (a[i] < item) pos++; if (pos == c_start) continue; while (item == a[pos]) pos += 1; if (pos != c_start) { swap(item, a[pos]); writes++; } while (pos != c_start) { pos = c_start; for (int i = c_start + 1; i < n; i++) if (a[i] < item) pos += 1; while (item == a[pos]) pos += 1; if (item != a[pos]) { swap(item, a[pos]); writes++; } } } } int main() { int a[] ={7,4,3,5,2,1,6}; int n = 7; cycleSort(a, n); for (int i = 0; i < n; i++) cout << a[i] << " "; return 0; }