MongoDB聚合框架按数组长度排序？
要按数组长度排序，请使用aggregate()。在此之前，使用$sum获取数组中的记录数。让我们创建包含文档的集合
> db.demo33.insertOne({"ListOfStudent":["Chris","Bob"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e17556ccfb11e5c34d898ca")
}
> db.demo33.insertOne({"ListOfStudent":["David","Adam","Mike"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e17557acfb11e5c34d898cb")
}
> db.demo33.insertOne({"ListOfStudent":["Carol","Sam","John","Robert"]});
{
"acknowledged" : true,
"insertedId" : ObjectId("5e1755a3cfb11e5c34d898cc")
}在find()方法的帮助下显示集合中的所有文档-
> db.demo33.find();
这将产生以下输出-
{ "_id" : ObjectId("5e17556ccfb11e5c34d898ca"), "ListOfStudent" : [ "Chris", "Bob" ] }
{ "_id" : ObjectId("5e17557acfb11e5c34d898cb"), "ListOfStudent" : [ "David", "Adam", "Mike" ] }
{ "_id" : ObjectId("5e1755a3cfb11e5c34d898cc"), "ListOfStudent" : [ "Carol", "Sam", "John", "Robert" ] }以下是按数组长度排序的查询-
> db.demo33.aggregate({$unwind:"$ListOfStudent"}, { $group : {_id:'$_id', ct:{$sum:1}}}, { $sort :{ ct: -1}} );这将产生以下输出-
{ "_id" : ObjectId("5e1755a3cfb11e5c34d898cc"), "ct" : 4 }
{ "_id" : ObjectId("5e17557acfb11e5c34d898cb"), "ct" : 3 }
{ "_id" : ObjectId("5e17556ccfb11e5c34d898ca"), "ct" : 2 }