hypot()函数以及C ++中的示例
C++hypot()
函数
hypot()函数是cmath标头的库函数,用于查找给定数字的斜边,接受两个数字并返回斜边的计算结果,即sqrt(x*x+y*y)。
hypot()
函数语法:
hypot(x, y);
参数:x,y–要计算的斜边数(或sqrt(x*x+y*y))
返回值:double-它返回double值,该值是表达式sqrt(x*x+y*y)的结果。
示例
Input: float x = 10.23; float y = 2.3; Function call: hypot(x, y); Output: 10.4854
C++代码演示hypot()
函数示例
//示例 //hypot()功能 #include <iostream> #include <cmath> using namespace std; //主代码部分 int main(){ float x = 10.23; float y = 2.3; //计算斜边 float result = hypot(x, y); cout<<"hypotenuse of "<<x<<" and "<<y<<" is = "<<result; cout<<endl; //使用sqrt()功能 result = sqrt((x*x + y*y)); cout<<"hypotenuse of "<<x<<" and "<<y<<" is = "<<result; cout<<endl; return 0; }
输出结果
hypotenuse of 10.23 and 2.3 is = 10.4854 hypotenuse of 10.23 and 2.3 is = 10.4854