fmod()函数以及C ++中的示例
C++floor()函数
fmod()函数是cmath标头的库函数，用于查找除法的余数，它接受两个数字（分子和分母），并返回四舍五入为零的分子/分母的浮点余数。
fmod()函数语法：
fmod(n, m);
参数：n，m–是用于计算除法余数的数字（分子，分母）。
返回值：double-返回double类型的值，该值是除法的浮点余数。
示例
Input:
float n = 5.3;
float m = 2;
Function call:
fmod(n,m);
Output:
1.3C++代码演示fmod()函数示例
//示例
//fmod()功能
#include <iostream>
#include <cmath>
using namespace std;
//main()部分
int main(){
float n;
float m;
float result;
//的值
//分子和分母
cout<<"Enter the value of numerator : ";
cin>>n;
cout<<"Enter the value of denominator: ";
cin>>m;
//找到余数
result = fmod(n,m);
cout<<"floating-point remainder of "<<n<<"/"<<m<<" is: ";
cout<<result<<endl;
return 0;
}输出结果
Enter the value of numerator: 5.3 Enter the value of denominator: 2 floating-point remainder of 5.3/2 is: 1.3 Second run: Enter the value of numerator: 18.5 Enter the value of denominator: 4.2 floating-point remainder of 18.5/4.2 is: 1.7 Third run: Enter the value of numerator: -36.23 Enter the value of denominator: 24.1 floating-point remainder of -36.23/24.1 is: -12.13 Fourth run: Enter the value of numerator: 36.23 Enter the value of denominator: -24.1 floating-point remainder of 36.23/-24.1 is: 12.13