Ruby中的多线程
Ruby多线程
如果我们谈论的是Ruby中的普通程序，那么所有语句都将按顺序执行，因为它曾经只有一个通常称为主线程的线程。但是我们的程序可能有多个线程，这个概念被称为多线程。多线程的优点是我们的程序使用更少的内存空间并共享相同的地址。借助这一概念，我们可以在同一时间执行多个任务。我们知道可以借助thread.new关键字创建一个新线程。
现在，让我们看看如何借助下面提供的示例创建多个线程：
=begin
Ruby program to demonstrate multithreading
=end
def Nhooo1
a = 0
while a <= 10
puts "Thread execution: #{a}"
sleep(1)
a = a + 1
end
end
def Nhooo2
b = 0
while b <= 5
puts "Thread2: #{b}"
sleep(2)
b = b + 1
end
end
x = Thread.new{Nhooo1()}
y = Thread.new{Nhooo2()}
x.join
y.join输出结果
RUN 1: Thread execution: 0 Thread2: 0 Thread execution: 1 Thread execution: 2 Thread2: 1 Thread execution: 3 Thread execution: 4 Thread2: 2 Thread execution: 5 Thread execution: 6 Thread2: 3 Thread execution: 7 Thread execution: 8 Thread2: 4 Thread execution: 9 Thread execution: 10 Thread2: 5 RUN 2: Thread execution: 0 Thread2: 0 Thread execution: 1 Thread2: 1 Thread execution: 2 Thread execution: 3 Thread2: 2 Thread execution: 4 Thread execution: 5 Thread2: 3 Thread execution: 6 Thread execution: 7 Thread2: 4 Thread execution: 8 Thread execution: 9 Thread2: 5 Thread execution: 10
在上面的示例中，即使程序没有变化，您也可以观察到两个输出都是不同的。这是因为线程的执行是基于它们的优先级执行的，并且默认情况下，所有线程都具有相同的优先级。它们的执行取决于指针。您还可以观察到两个线程同时执行。
线程也可以在程序中使用相同的资源，请参考以下示例，
=begin
Ruby program to demonstrate multithreading
using same resource
=end
$g_var = 10
def Nhooo1
a = 0
while a <= 10
puts "Thread execution: #{a}"
sleep(1)
a = a + 1
end
puts "Inside Thread 1 ; #{$g_var+19}"
end
def Nhooo2
b = 0
while b <= 5
puts "Thread2: #{b}"
sleep(2)
b = b + 1
end
puts "Inside Thread 2 ; #{$g_var+10}"
end
x = Thread.new{Nhooo1()}
y = Thread.new{Nhooo2()}
x.join
y.join输出结果
Thread execution: 0 Thread2: 0 Thread execution: 1 Thread execution: 2 Thread2: 1 Thread execution: 3 Thread2: 2 Thread execution: 4 Thread execution: 5 Thread2: 3 Thread execution: 6 Thread execution: 7 Thread2: 4 Thread execution: 8 Thread execution: 9 Thread2: 5 Thread execution: 10 Inside Thread 1 ; 29 Inside Thread 2 ; 20
在上面的代码中，您可以观察到存在一个名为$g_var的全局变量名称。两个线程都可以访问它，但是当它们操纵它的值时，它不会对其他线程操纵的值产生任何影响。