Ruby until 循环示例
until循环
until循环是Ruby的强大功能，这使得它与其他编程语言不同的一个。对直到循环的支持指定了Ruby用户友好语言是多少？
until循环是while循环，如果我们在功能方面证明它正好相反。只要布尔条件为假，就执行while循环，但是直到until循环，只要布尔条件不为真，就执行while循环。这是进入控制循环的示例，其中在执行循环主体之前检查指定的条件。
使用以下语法可以实现until循环：
until conditional [do]
# 要执行的代码
end范例1：
=begin
Ruby program to print a message 10 times using until loop
=end
num=0
until num==10
puts "Hello there! Message from nhooo.com! Happy learning!"
num=num+1
end输出结果
Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning! Hello there! Message from nhooo.com! Happy learning!
范例2：
=begin
Ruby program to find the sum of all
digits of given number using until loop
=end
puts "Enter the number"
num=gets.chomp.to_i
temp=num
sum = 0
until num==0
#直到循环的实现
rem=num%10
num=num/10
sum=sum+rem
end
puts "The sum of #{temp} is #{sum}"输出结果
Enter the number 456672 The sum of 456672 is 30
范例3：
=begin
Ruby program to find the count of even
and odd digits in the given number
using until loop
=end
puts "Enter the number"
num=gets.chomp.to_i
temp=num
evecount=0
oddcount=0
until num==0
#直到循环的实现
rem=num%10
num=num/10
if rem%2==0
puts "#{rem} is even"
evecount+=1
else
puts "#{rem} is odd"
oddcount+=1
end
end
puts "Number of even numbers are #{evecount}"
puts "Number of odd numbers are #{oddcount}"输出结果
Enter the number 7896532 2 is even 3 is odd 5 is odd 6 is even 9 is odd 8 is even 7 is odd Number of even numbers are 3 Number of odd numbers are 4