Python中的矩阵乘法
对于两个矩阵的乘法A和B，在A柱的数量应该等于在B.行为了得到乘积矩阵的元素的数量，我们取第i个A的行和k个B的柱，将它们逐个元素相乘并取所有这些乘积的总和。
在Python中将两个矩阵相乘的程序
import random
m1=input("Enter No. of rows in the first matrix: ")
n1=input("Enter No. of columns in the first matrix: ")
a = [[random.random() for col in range(n1)] for row in range(m1)]
for i in range(m1):
for j in range(n1):
a[i][j]=input()m2=input ("Enter No. of rows in the second matrix: ")
n2=input ("Enter No. of columns in the second matrix: ")
b = [[random.random() for col in range(n2)] for row in range(m2)]
for i in range(m2):
for j in range(n2):
b[i][j]=input()c=[[random.random()for col in range(n2)]for row in range(m1)]
if (n1==m2):
for i in range(m1):
for j in range(n2):
c[i][j]=0
for k in range(n1):
c[i][j]+=a[i][k]*b[k][j]
print c[i][j],'\t',
print
else:
print "Multiplication not possible"输出结果
Enter No. of rows in the first matrix: 3 Enter No. of columns in the first matrix: 2 1 2 3 4 5 6 Enter No. of rows in the second matrix: 2 Enter No. of columns in the second matrix: 3 1 2 3 4 5 6 Output: 9 12 15 19 26 33 29 40 51
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