Java如何使用勉强的量词正则表达式？

2024-04-16 11:22:03 355

package org.nhooo.example.regex; import java.util.regex.Matcher; import java.util.regex.Pattern; public class ReluctantQuantifierDemo { public static void main(String[] args) { String[] expressions = {"x??", "x*?", "x+?", "x{2}?", "x{2,}?", "x{2,5}?"}; String input = "xxxxxxx"; for (String expression : expressions) { Pattern pattern = Pattern.compile(expression); Matcher matcher = pattern.matcher(input); //查找每个匹配并打印 System.out.println("------------------------------"); System.out.format("regex: %s %n", expression); while (matcher.find()) { System.out.format("Text \"%s\" found at %d to %d%n", matcher.group(), matcher.start(), matcher.end()); } } } }

regex: x?? Text "" found at 0 to 0 Text "" found at 1 to 1 Text "" found at 2 to 2 Text "" found at 3 to 3 Text "" found at 4 to 4 Text "" found at 5 to 5 Text "" found at 6 to 6 Text "" found at 7 to 7 ------------------------------ regex: x*? Text "" found at 0 to 0 Text "" found at 1 to 1 Text "" found at 2 to 2 Text "" found at 3 to 3 Text "" found at 4 to 4 Text "" found at 5 to 5 Text "" found at 6 to 6 Text "" found at 7 to 7 ------------------------------ regex: x+? Text "x" found at 0 to 1 Text "x" found at 1 to 2 Text "x" found at 2 to 3 Text "x" found at 3 to 4 Text "x" found at 4 to 5 Text "x" found at 5 to 6 Text "x" found at 6 to 7 ------------------------------ regex: x{2}? Text "xx" found at 0 to 2 Text "xx" found at 2 to 4 Text "xx" found at 4 to 6 ------------------------------ regex: x{2,}? Text "xx" found at 0 to 2 Text "xx" found at 2 to 4 Text "xx" found at 4 to 6 ------------------------------ regex: x{2,5}? Text "xx" found at 0 to 2 Text "xx" found at 2 to 4 Text "xx" found at 4 to 6

Java如何使用勉强的量词正则表达式？

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