C#获取两个时间的时间差并去除周末（取工作日）的方法
本文实例讲述了C#获取两个时间的时间差并去除周末的方法。分享给大家供大家参考。具体分析如下：
一般来说取时间差的代码很多，但是能够只取工作日的时间差的代码很少，这段代码就来实现这一功能。
protectedvoidPage_Load(objectsender,EventArgse)
{
DateTimestart=Convert.ToDateTime("2012-12-10");
DateTimeend=Convert.ToDateTime("2012-12-18");
TimeSpanspan=end-start;
//inttotleDay=span.Days;
//DateTimespanNu=DateTime.Now.Subtract(span);
intAllDays=Convert.ToInt32(span.TotalDays)+1;//差距的所有天数
inttotleWeek=AllDays/7;//差别多少周
intyuDay=AllDays%7;//除了整个星期的天数
intlastDay=0;
if(yuDay==0)//正好整个周
{
lastDay=AllDays-(totleWeek*2);
}
else
{
intweekDay=0;
intendWeekDay=0;//多余的天数有几天是周六或者周日
switch(start.DayOfWeek)
{
caseDayOfWeek.Monday:
weekDay=1;
break;
caseDayOfWeek.Tuesday:
weekDay=2;
break;
caseDayOfWeek.Wednesday:
weekDay=3;
break;
caseDayOfWeek.Thursday:
weekDay=4;
break;
caseDayOfWeek.Friday:
weekDay=5;
break;
caseDayOfWeek.Saturday:
weekDay=6;
break;
caseDayOfWeek.Sunday:
weekDay=7;
break;
}
if((weekDay==6&&yuDay>=2)||(weekDay==7&&yuDay>=1)||(weekDay==5&&yuDay>=3)||(weekDay==4&&yuDay>=4)||(weekDay==3&&yuDay>=5)||(weekDay==2&&yuDay>=6)||(weekDay==1&&yuDay>=7))
{
endWeekDay=2;
}
if((weekDay==6&&yuDay<1)||(weekDay==7&&yuDay<5)||(weekDay==5&&yuDay<2)||(weekDay==4&&yuDay<3)||(weekDay==3&&yuDay<4)||(weekDay==2&&yuDay<5)||(weekDay==1&&yuDay<6)){
endWeekDay=1;
}
lastDay=AllDays-(totleWeek*2)-endWeekDay;
}
lblTime.Text=lastDay.ToString();
}
希望本文所述对大家的C#程序设计有所帮助。