Python中type的构造函数参数含义说明
测试代码如下：
classModelMetaClass(type):
def__new__(cls,name,base,attrs):
logging.info("clsis:"+str(cls))
logging.info("nameis:"+str(name))
logging.info("baseis:"+str(base))
logging.info("attrsis:"+str(attrs))
returntype.__new__(cls,name,base,attrs)
pass
pass
classModel(dict):
__metaclass__=ModelMetaClass
def__init__(self):
pass
pass
defmain():
m=Model()
if__name__=='__main__':
main()
测试结果：
INFO:root:clsis:<class'__main__.ModelMetaClass'>
INFO:root:nameis:Model
INFO:root:baseis:(<type'dict'>,)
INFO:root:attrsis:{'__module__':'__main__','__metaclass__':<class'__main__.ModelMetaClass'>,'__init__':<function__init__at0x025C76F0>}
结论就显而易见了。cls是当前类的名字，即类本身。name是通过__metaclass__属性指向ModelMetaClass的类，即要实例化的类，ModelMetaClass拦截了该类的实例化。base是要实例化的类的基类。attrs是要实例化的类的属性集合。