python实现将英文单词表示的数字转换成阿拉伯数字的方法
本文实例讲述了python实现将英文单词表示的数字转换成阿拉伯数字的方法。分享给大家供大家参考。具体实现方法如下：
importre
_known={
'zero':0,
'one':1,
'two':2,
'three':3,
'four':4,
'five':5,
'six':6,
'seven':7,
'eight':8,
'nine':9,
'ten':10,
'eleven':11,
'twelve':12,
'thirteen':13,
'fourteen':14,
'fifteen':15,
'sixteen':16,
'seventeen':17,
'eighteen':18,
'nineteen':19,
'twenty':20,
'thirty':30,
'forty':40,
'fifty':50,
'sixty':60,
'seventy':70,
'eighty':80,
'ninety':90
}
defspoken_word_to_number(n):
"""Assumenisapositiveinteger".
assert_positive_integer_number('ninehundred')==900
assertspoken_word_to_number('onehundred')==100
assertspoken_word_to_number('eleven')==11
assertspoken_word_to_number('twentytwo')==22
assertspoken_word_to_number('thirty-two')==32
assertspoken_word_to_number('fortytwo')==42
assertspoken_word_to_number('twohundredthirtytwo')==232
assertspoken_word_to_number('twothirtytwo')==232
assertspoken_word_to_number('nineteenhundredeightynine')==1989
assertspoken_word_to_number('nineteeneightynine')==1989
assertspoken_word_to_number('onethousandninehundredandeightynine')==1989
assertspoken_word_to_number('nineeighty')==980
assertspoken_word_to_number('ninetwo')==92#wontbeabletoconvertthisone
assertspoken_word_to_number('ninethousandninehundred')==9900
assertspoken_word_to_number('onethousandninehundredone')==1901
"""
n=n.lower().strip()
ifnin_known:
return_known[n]
else:
inputWordArr=re.split('[-]',n)
assertlen(inputWordArr)>1#allsinglewordsareknown
#Checkthepathologicalcasewherehundredisattheendorthousandisatend
ifinputWordArr[-1]=='hundred':
inputWordArr.append('zero')
inputWordArr.append('zero')
ifinputWordArr[-1]=='thousand':
inputWordArr.append('zero')
inputWordArr.append('zero')
inputWordArr.append('zero')
ifinputWordArr[0]=='hundred':
inputWordArr.insert(0,'one')
ifinputWordArr[0]=='thousand':
inputWordArr.insert(0,'one')
inputWordArr=[wordforwordininputWordArrifwordnotin['and','minus','negative']]
currentPosition='unit'
prevPosition=None
output=0
forwordinreversed(inputWordArr):
ifcurrentPosition=='unit':
number=_known[word]
output+=number
ifnumber>9:
currentPosition='hundred'
else:
currentPosition='ten'
elifcurrentPosition=='ten':
ifword!='hundred':
number=_known[word]
ifnumber<10:
output+=number*10
else:
output+=number
#else:nothingspecial
currentPosition='hundred'
elifcurrentPosition=='hundred':
ifwordnotin['hundred','thousand']:
number=_known[word]
output+=number*100
currentPosition='thousand'
elifword=='thousand':
currentPosition='thousand'
else:
currentPosition='hundred'
elifcurrentPosition=='thousand':
assertword!='hundred'
ifword!='thousand':
number=_known[word]
output+=number*1000
else:
assert"Can'tbehere"==None
return(output)
希望本文所述对大家的Python程序设计有所帮助。