PHP获取一年有几周以及每周开始日期和结束日期
最近接了一个项目，其中有一需求是用php获取一年有几周以及每周开始日期和接触日期。在网上找些资料没有合适的，于是自己做了一份，下面通过两种方式实现PHP获取一年有几周以及每周开始日期和结束日期
代码一：
<?php
header("Content-type:text/html;charset=utf-8");
date_default_timezone_set("Asia/Shanghai");
$year=(int)$_GET['year'];
$week=(int)$_GET['week'];
$weeks=date("W",mktime(0,0,0,12,28,$year));
echo$year.'年一共有'.$weeks.'周<br/>';
if($week>$weeks||$week<=0)
{
$week=1;
}
if($week<10)
{
$week='0'.$week;
}
$timestamp['start']=strtotime($year.'W'.$week);
$timestamp['end']=strtotime('+1week-1day',$timestamp['start']);
echo$year.'年第'.$week.'周开始时间戳：'.$timestamp['start'].'<br/>';
echo$year.'年第'.$week.'周结束时间戳：'.$timestamp['end'].'<br/>';
echo$year.'年第'.$week.'周开始日期：'.date("Y-m-d",$timestamp['start']).'<br/>';
echo$year.'年第'.$week.'周结束日期：'.date("Y-m-d",$timestamp['end']);
?>
代码二：
<?php
header("Content-type:text/html;charset=utf-8");
functiongetIsoWeeksInYear($year)
{
$date=newDateTime;
$date->setISODate($year,53);
return($date->format("W")==="53"?53:52);
}
functionweekday($custom_date)
{
$week_start=date('d-m-Y',strtotime('thisweekmonday',$custom_date));
$week_end=date('d-m-Y',strtotime('thisweeksunday',$custom_date));
$week_array[0]=$week_start;
$week_array[1]=$week_end;
return$week_array;
}
echo'<br>Weeksin2013<br>'.getIsoWeeksInYear(2013);
$weekday=weekday(strtotime(date('d-m-Y',strtotime('5-8-2013'))));
echo'<br>10-8-2013';
echo'<br>Start:'.$weekday[0];
echo'<br>End:'.$weekday[1];
?>
以上本文的全部内容，希望对大家学习PHP获取一年有几周以及每周开始日期和结束日期，有所帮助。