如何用C语言编写一个简单的计算器程序?
首先编写C代码以创建一个简单的计算器。然后,按照下面给出的算法编写一个C程序。
算法
Step 1: Declare variables Step 2: Enter any operator at runtime Step 3: Enter any two integer values at runtime Step 4: Apply switch case to select the operator: //情况'+':结果=num1+num2; break; case '-': result = num1 - num2; break; case '*': result = num1 * num2; break; case '/': result = num1 / num2; break; default: printf("\n Invalid Operator "); Step 5: Print the result
示例
以下是使用SwitchCase的计算器C程序-
#include <stdio.h> int main(){ char Operator; float num1, num2, result = 0; printf("\n Enter any one operator like +, -, *, / : "); scanf("%c", &Operator); printf("Enter the values of Operands num1 and num2 \n : "); scanf("%f%f", &num1, &num2); switch(Operator){ case '+': result = num1 + num2; break; case '-': result = num1 - num2; break; case '*': result = num1 * num2; break; case '/': result = num1 / num2; break; default: printf("\n Invalid Operator "); } printf("The value = %f", result); return 0; }输出结果
执行以上程序后,将产生以下结果-
Enter any one operator: + Enter values of Operands num1 and num2: 23 45 The value = 68.000000