YII框架中搜索分页jQuery写法详解
控制层
usefrontend\models\StudUser;
useyii\data\Pagination;
useyii\db\Query;
/**
*查询
*
*/
publicfunctionactionSearch()
{
//接值
$where=Yii::$app->request->get();
//实例化query
$query=newQuery();
$query->from('stud_user');
//判断
if(isset($where['sex'])&&$where['sex']!=''){
//判断
if($where['sex']=='男'){
$query->andWhere(['stud_sex'=>0]);
}
if($where['sex']=='女'){
$query->andWhere(['stud_sex'=>1]);
}
}else{
$where['sex']='';
}
//年龄
if(isset($where['age'])&&$where['age']!=''){
$query->andWhere(['>','stud_age',$where['age']]);
}else{
$where['age']='';
}
//分页
$pagination=newPagination(['totalCount'=>$query->count()]);
//条数
$pagination->setPageSize('3');
//条件
$query->offset($pagination->offset)->limit($pagination->limit);
//执行
$userInfo=$query->all();
//print_r($userInfo);die;
return$this->render('search',['userInfo'=>$userInfo,'page'=>$pagination,'where'=>$where]);
}
模型层
<?php
namespacefrontend\models;
useYii;
useyii\db\ActiveRecord;
classStudUserextendsActiveRecord
{
/**
*声明表名
*
*/
publicstaticfunctiontableName()
{
return'{{%stud_user}}';
}
/**
*验证规则
*
*/
publicfunctionrules()
{
return[
['stud_age','integer'],
];
}
}
视图层
<?php
useyii\widgets\ActiveForm;
useyii\helpers\Url;
useyii\helpers\Html;
useyii\widgets\LinkPager;
?>
<?php
$form=ActiveForm::begin([
'action'=>Url::toRoute(['admin/search']),
'method'=>'get',
]);
echo'性别'," ",Html::input('text','sex',$where['sex']);
echo'年龄'," ",Html::input('text','age',$where['age']);
echoHtml::submitButton('提交');
ActiveForm::end();
?>
<tableclass="table">
<tr>
<td>序号</td>
<td>姓名</td>
<td>年龄</td>
</tr>
<?phpforeach($userInfoas$val):?>
<tr>
<td><?=$val['stud_id']?></td>
<td><?=$val['stud_name']?></td>
<td><?=$val['stud_age']?></td>
</tr>
<?phpendforeach;?>
</table>
<?php
echoLinkPager::widget([
'pagination'=>$page,
'nextPageLabel'=>'下一页'
]);?>
分页的样式在
LinkPager.php中
以上所述是小编给大家介绍的YII框架中搜索分页jQuery写法详解，希望对大家有所帮助，如果大家有任何疑问请给我留言，小编会及时回复大家的。在此也非常感谢大家对毛票票网站的支持！