编写C程序以查找给定数字的二进制补码
给定二进制数的二进制补码可以通过以下两种方法计算：
方法1-将给定的二进制数转换为一个补数，然后加1。
方法2-从最低有效位(LSB)的第一个位开始算起的尾随零，包括一个保持不变且剩余的所有零，应进行补码。
查找给定二进制数的二进制补码的逻辑如下-
for(i = SIZE - 1; i >= 0; i--){
if(one[i] == '1' && carry == 1){
two[i] = '0';
}else if(one[i] == '0' && carry == 1){
two[i] = '1';
carry = 0;
}else{
two[i] = one[i];
}
}
two[SIZE] = '\0';
printf("Two's complement of binary number %s is %s\n",num, two);从给定的二进制数中找到一个补码的逻辑是-
for(i = 0; i < SIZE; i++){
if(num[i] == '0'){
one[i] = '1';
}else if(num[i] == '1'){
one[i] = '0';
}
}
one[SIZE] = '\0';
printf("Ones' complement of binary number %s is %s\n",num, one);示例
以下是C程序来查找给定数字的二进制补码-
#include<stdio.h>
#include<stdlib.h>
#define SIZE 8
int main(){
int i, carry = 1;
char num[SIZE + 1], one[SIZE + 1], two[SIZE + 1];
printf("Enter the binary number\n");
gets(num);
for(i = 0; i < SIZE; i++){
if(num[i] == '0'){
one[i] = '1';
}
else if(num[i] == '1'){
one[i] = '0';
}
}
one[SIZE] = '\0';
printf("Ones' complement of binary number %s is %s\n",num, one);
for(i = SIZE - 1; i >= 0; i--){
if(one[i] == '1' && carry == 1){
two[i] = '0';
}else if(one[i] == '0' && carry == 1){
two[i] = '1';
carry = 0;
}else{
two[i] = one[i];
}
}
two[SIZE] = '\0';
printf("Two's complement of binary number %s is %s\n",num, two);
return 0;
}输出结果执行以上程序后，将产生以下结果-
Enter the binary number 1000010 Ones' complement of binary number 1000010 is 0111101 Two's complement of binary number 1000010 is 0111110
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