JavaScript实现构造json数组的方法分析
本文实例讲述了JavaScript实现构造json数组的方法。分享给大家供大家参考,具体如下:
从后端拿到的数据是一个数组,每个元素中包含的数据如下(host相同的记录都是相邻的)
currentTime:"1470729601"
host:"10.3.34.21"
taskList:null
taskNum:1
想构造类似如下结构的json数组
[{ name:'host:10.1.6.49', data:[ [1470641461000,5], [1470642581000,4], [1470643701000,2], [1470647341000,3] ] },{ name:'host:10.3.34.18', data:[ [1470641461000,2], [1470642581000,2], [1470643701000,1], [1470647341000,4] ] },{ name:'host:10.2.2.22', data:[ [1470641461000,3], [1470642581000,2], [1470643701000,6], [1470647341000,4] ] },{ name:'host:10.1.110.96', data:[ [1470641461000,1], [1470642581000,8], [1470643701000,1], [1470647341000,1] ] },{ name:'host:10.2.2.87', data:[ [1470641461000,7], [1470642581000,3], [1470643701000,6], [1470647341000,5] ] }]
错误的方式:
varbackendData=data.result; varresultList=newArray(); varcurHost=""; varoneHostDataList=newArray(); for(variinbackendData){ varhost=backendData[i].host; if(host!=curHost){ if(i!=0){ varitem=newObject(); item.name=curHost; item.data=oneHostDataList; resultList.push(item); } oneHostDataList=newArray(); curHost=host; } else{ vardot=newArray(); dot.push(backendData[i].currentTime*1000); dot.push(backendData[i].taskNum); oneHostDataList.push(dot); } } varitem=newObject(); item.name=curHost; item.data=oneHostDataList; resultList.push(item); $scope.data=JSON.stringify(resultList);
以上方式的问题在于转换后会使得name和host和带上引号,正确的方式如下:
varbackendData=data.result; varresultList=[]; varcurHost=""; varoneHostDataList=newArray(); for(variinbackendData){ varhost=backendData[i].host; if(host!=curHost){ if(i!=0){ varitem={ name:curHost, data:oneHostDataList }; resultList.push(item); } oneHostDataList=newArray(); curHost=host; } else{ vardot=newArray(); dot.push(backendData[i].currentTime*1000); dot.push(backendData[i].taskNum); oneHostDataList.push(dot); } } varitem=newObject(); item.name=curHost; item.data=oneHostDataList; resultList.push(item); $scope.data=resultList;
PS:这里再为大家推荐几款相关的json在线工具供大家参考:
在线
JSON在线格式化工具:
http://tools.jb51.net/code/jsonformat
在线XML/