ASP中格式化时间短日期补0变两位长日期的方法
因为短日期不足2位，所以在网页排版的时候，影响美观，下面两个函数可以解决这个问题。
2020-2-7短日期变2020-02-07长日期
FunctionFStime(times)
Dimyears,months,days
iflen(times)=0thenexitfunction
years=year(times)
months=right("0"&month(times),2)
days=right("0"&day(times),2)
times=years&"-"&months&"-"&days
FStime=times
EndFunction
2020-2-723:37:5短日期变2020-02-0723:37:05长日期
FunctionFLtime(times)
Dimyears,months,days,hours,minutes,seconds
iflen(times)=0thenexitfunction
years=year(times):months=right("0"&month(times),2)
days=right("0"&day(times),2):hours=right("0"&hour(times),2)
minutes=right("0"&minute(times),2):seconds=right("0"&second(times),2)
FLtime=years&"-"&months&"-"&days&""&hours&":"&minutes&":"&seconds
EndFunction
Pw_Sys日期格式转换函数
<%
RemPw_Sys日期格式转换函数
functionDateTimeFormat(DateTime,Format)
selectcaseFormat
case"1"
DateTimeFormat=""&year(DateTime)&"年"&month(DateTime)&"月"&Right("0"&Day(DateTime),2)&"日"
case"2"
DateTimeFormat=""&month(DateTime)&"月"&Right("0"&Day(DateTime),2)&"日"
case"3"
DateTimeFormat=""&year(DateTime)&"-"&month(DateTime)&"-"&Right("0"&Day(DateTime),2)&""
case"4"
DateTimeFormat=""&year(DateTime)&"/"&month(DateTime)&"/"&Right("0"&Day(DateTime),2)&""
case"5"
DateTimeFormat=""&month(DateTime)&"/"&Right("0"&Day(DateTime),2)&""
case"6"
DateTimeFormat=""&year(DateTime)&"年"&month(DateTime)&"月"&Right("0"&Day(DateTime),2)&"日"&FormatDateTime(DateTime,4)&""
case"7"
temp="星期日,星期一,星期二,星期三,星期四,星期五,星期六"
temp=split(temp,",")
DateTimeFormat=temp(WeekRight("0"&Day(DateTime),2)-1)
case"8"
DateTimeFormat=""&month(DateTime)&"-"&Right("0"&Day(DateTime),2)&""
case"9"
iflen(hour(DateTime))=1then
str="0"&hour(DateTime)
else
str=hour(DateTime)
endif
DateTimeFormat=DateTimeFormat(DateTime,1)&""&str&":"&Minute(DateTime)
case"10"
DateTimeFormat=""&year(DateTime)&"年"&month(DateTime)&"月"
caseelse
DateTimeFormat=DateTime
endselect
endfunction
%>
程序代码（把yyyy-mm-dd格式的日期中的月份和日期转换成两位数字的方法）
dimtoday
today=Date'避免重复调用Date，所以赋值给一个变量
today=Year(today)&"-"&Right("0"&Month(today),2)&"-"&Right("0"&Day(today),2)
asp中一段自动补位的函数
functionformatsn(getnum,getbit) dimformatsnnum,formatsnpre,formatsnj formatsnnum=getbit–len(getnum) forformatsnj=1toformatsnnum formatsnpre=formatsnpre&"0" next formatsn=formatsnpre&getnum endfunction
使用方法
formatsn(getnum,getbit)
getnum计数
getbit共几位
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