C程序在两个数组上执行交集运算

2023-06-21 20:42:02 261

交集运算

如果数组1={1,2,3,4,6}

数组2={1,2,5,6,7}

然后，array1和array2的交集是

Array1 ^ array 2 = {1,2,3,4,6} ^ {1,2,5,6,7} = {1,2,6}

一组公共元素称为交集。

交集的逻辑如下-

k=0; for(i=0;i

程序

以下是在两个数组上执行交集运算的C程序-

#include
int removerepeated(int size,int a[]);
void sort(int size,int a[]);
main(){
   int i,size1,size2,size,j=0,k,intersectionsize;
   printf("Enter size of an array1\n");
   scanf("%d",&size1);
   printf("Enter size of an array2\n");
   scanf("%d",&size2);
   int a[size1],b[size2],uni[size1+size2];
   if(size1size2){
      intersectionsize=size2;
   }else{
      intersectionsize=size1;
   }
   int intersection[intersectionsize];
   printf("Enter numbers for array 1\n");
   for(i=0;i0){
      for(i=0;ia[j]){
            temp=a[i];
            a[i]=a[j];
            a[j]=temp;
         }
      }
   }
}

输出结果

执行以上程序后，将产生以下结果-

Enter size of an array1
5
Enter size of an array2
2
Enter numbers for array 1
4
5
6
7
8
Enter numbers for array 2
4
1
Array after intersection
4

C程序在两个数组上执行交集运算

交集运算

程序

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