Python程序检查两个列表是否至少有一个公共元素
在这个问题中我们使用了两个用户输入列表。我们的任务是检查是否有任何共同元素。我们使用非常简单的遍历技术，遍历列表并检查第一个列表和第二个列表的每个元素。
示例
Input : A = [10, 20, 30, 50]
B = [90, 80, 30, 10, 3]
Output : FOUND
Input : A = [10, 20, 30, 50]
B = [100,200,300,500]
Output : NOT FOUND算法
commonelement(A,B) /* A and B are two user input list */ Step 1: First use one third variable c which is display the result. Step 2: Traverse both the list and compare every element of the first list with every element of the second list. Step 3: If common element is found then c display FOUND otherwise display NOT FOUND.
示例代码
#要检查的Python程序
#如果两个列表至少有
#一个元素共同
#使用列表遍历
def commonelement(A, B):
c = "NOT FOUND"
#遍历第一个列表
for i in A:
#遍历第二个列表
for j in B:
#如果一个共同
if i == j:
c="FOUND"
return c
return c
#驱动程序代码
A=list()
B=list()
n1=int(input("Enter the size of the first List ::"))
print("Enter the Element of first List ::")
for i in range(int(n1)):
k=int(input(""))
A.append(k)
n2=int(input("Enter the size of the second List ::"))
print("Enter the Element of second List ::")
for i in range(int(n2)):
k=int(input(""))
B.append(k)
print("Display Result ::",commonelement(A, B)) 输出结果Enter the size of the first List ::4 Enter the Element of first List :: 2 1 4 9 Enter the size of the second List ::5 Enter the Element of second List :: 9 90 4 89 67 Display Result :: FOUND Enter the size of the first List ::4 Enter the Element of first List :: 67 89 45 23 Enter the size of the second List ::4 Enter the Element of second List :: 1 2 3 4 Display Result :: NOT FOUND