如何从日期时间列中仅选择 MySQL 日期？
为此使用DATE_FORMAT。让我们首先创建一个表-
mysql> create table DemoTable
(
ShippingDate varchar(200)
);使用插入命令在表中插入一些记录-
mysql> insert into DemoTable values('04:58 PM 10/31/2018');
mysql> insert into DemoTable values('02:30 AM 01/01/2019');
mysql> insert into DemoTable values('12:01 AM 05/03/2019');使用select语句显示表中的所有记录-
mysql> select *from DemoTable;
这将产生以下输出-
+---------------------+ | ShippingDate | +---------------------+ | 04:58 PM 10/31/2018 | | 02:30 AM 01/01/2019 | | 12:01 AM 05/03/2019 | +---------------------+ 3 rows in set (0.00 sec)
以下是仅从日期时间列中选择日期的查询-
mysql> SELECT DATE_FORMAT(STR_TO_DATE(ShippingDate, '%h:%i %p %m/%d/%Y'), '%m/%d/%Y') from DemoTable;
这将产生以下仅显示日期的输出-
+-------------------------------------------------------------------------+ | DATE_FORMAT(STR_TO_DATE(ShippingDate, '%h:%i %p %m/%d/%Y'), '%m/%d/%Y') | +-------------------------------------------------------------------------+ | 10/31/2018 | | 01/01/2019 | | 05/03/2019 | +-------------------------------------------------------------------------+ 3 rows in set (0.00 sec)