Python - 计算 Pandas DataFrame 的列值的最小值
要获得列值的最小值，请使用该min()函数。首先，导入所需的Pandas库-
import pandas as pd
现在，创建一个包含两列的DataFrame-
dataFrame1 = pd.DataFrame(
{
"Car": ['BMW', 'Lexus', 'Audi', 'Tesla', 'Bentley', 'Jaguar'],"Units": [100, 150, 110, 80, 110, 90] }
)使用min()-查找单列“单位”的最小值-
print"Minimum Units from DataFrame1 = ",dataFrame1['Units'].min()
用同样的方法，我们计算从2最小值次数据帧。
示例
以下是完整的代码-
import pandas as pd
#创建DataFrame1
dataFrame1 = pd.DataFrame(
{
"Car": ['BMW', 'Lexus', 'Audi', 'Tesla', 'Bentley', 'Jaguar'],"Units": [100, 150, 110, 80, 110, 90] }
)
print"DataFrame1 ...\n",dataFrame1
# Finding minimum value of a single column "Units"
print"Minimum Units from DataFrame1 = ",dataFrame1['Units'].min()
#创建DataFrame2
dataFrame2 = pd.DataFrame(
{
"Product": ['TV', 'PenDrive', 'HeadPhone', 'EarPhone', 'HDD', 'SSD'],"Price": [8000, 500, 3000, 1500, 3000, 4000]
}
)
print"\nDataFrame2 ...\n",dataFrame2
# Finding minimum value of a single column "Price"
print"Minimum Price from DataFrame2 = ",dataFrame2['Price'].min()输出结果这将产生以下输出-
DataFrame1 ...
Car Units
0 BMW 100
1 Lexus 150
2 Audi 110
3 Tesla 80
4 Bentley 110
5 Jaguar 90
Minimum Units from DataFrame1 = 80
DataFrame2 ...
Price Product
0 8000 TV
1 500 PenDrive
2 3000 HeadPhone
3 1500 EarPhone
4 3000 HDD
5 4000 SSD
Minimum Price from DataFrame2 = 500